document.write( "Question 1180956: As measured by the Stanford-Binet test, IQ scores are approximately normally distributed with mean 100 and standard deviation 16. Mensa is an organization whose members have IQ scores in the top 2% of the population. To be admitted to Mensa, a person\'s Stanford-Binet IQ score is at least:
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document.write( "A. 100 - (16 x 2.05) = 67.20.
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document.write( "B. 100 - (16 x 0.98) = 84.32.
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document.write( "C. 100 + (16 x 2.05) = 132.80
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document.write( "D. 100 + (16 x 0.98) = 1 5.68 \n" );
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Algebra.Com's Answer #811068 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! It is C. \n" ); document.write( "z=(x-mean)/sd \n" ); document.write( "so 2.05=(x-mean)/16 \n" ); document.write( "x=mean+(16*2.05) \n" ); document.write( "It also has to be well over 100. \n" ); document.write( " |