document.write( "Question 111199: I keep getting stuck on this problem (below is what I keep getting)
\n" ); document.write( "The problem is....Solve for xby completing the square: x^2+6x=2\r
\n" ); document.write( "\n" ); document.write( "What I can get
\n" ); document.write( "x^2+6x=2
\n" ); document.write( "6x^2=2
\n" ); document.write( "6(x^2)=2\r
\n" ); document.write( "\n" ); document.write( "I cant get any further, can you please tell me what i did wrong. Thank you so much!!!!
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Algebra.Com's Answer #81105 by Earlsdon(6294)\"\" \"About 
You can put this solution on YOUR website!
Solve for x by completing the square:
\n" ); document.write( "\"x%5E2%2B6x+=+2\" Complete the square in x by adding the square of half the x-coefficient to both sides, this is: \"%286%2F2%29%5E2+=+9\"
\n" ); document.write( "\"x%5E2%2B6x%2B9+=+2%2B9\" Now factor the left side.
\n" ); document.write( "\"%28x%2B3%29%5E2+=+11\" Now take the square root of both sides. You'll get two answers.
\n" ); document.write( "\"x%2B3+=+sqrt%2811%29\" or \"x%2B3+=+-sqrt%2811%29\" Now subtract 3 from both sides in each of these.
\n" ); document.write( "\"x+=+-3%2Bsqrt%2811%29\" or \"x+=+-3-sqrt%2811%29\" ...and these are the two roots.
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