document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1181173>Question 1181173</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a grocer sells Brazilian coffee at R30 per kilogram and Colombian coffee at R51 per kilogram.calculate how many kilograms of each should he mix to have a blend of 50 kilograms that he can sell at R42.60 per kilogram </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #811010 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13200)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=811010\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "First a standard algebraic solution....<br><BR>\n" );
document.write( "x kg at R30 per kg, plus (50-x) kg at R51 per kg, equals 50 kg at 42.60 per kg:<br><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=30%28x%29%2B51%2850-x%29=42.6%2850%29 ALIGN=MIDDLE  ALT=\"30%28x%29%2B51%2850-x%29=42.6%2850%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=30x%2B2550-51x=2130 ALIGN=MIDDLE  ALT=\"30x%2B2550-51x=2130\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=-21x=-420 ALIGN=MIDDLE  ALT=\"-21x=-420\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x=-420%2F-21=20 ALIGN=MIDDLE  ALT=\"x=-420%2F-21=20\"   DISABLED_style= \"max-width:90%; height:auto;\" ><br><BR>\n" );
document.write( "ANSWER: x=20kg of the Brazilian; 50-x=30kg of the Colombian.<br><BR>\n" );
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document.write( "And now an easy path to the answer if a formal algebraic solution is not required....<br><BR>\n" );
document.write( "Look at the three prices per kg on a number line -- 30, 42.60, and 51 -- and determine that 42.60 is 12.60/21 = 0.6 = 3/5 of the way from 30 to 51.<br><BR>\n" );
document.write( "That means 3/5 of the mixture should be the higher priced Colombian coffee.<br><BR>\n" );
document.write( "ANSWER: 3/5 of 50kg, or 30kg, of Colombian and the other 20kg of Brazilian.<br><BR>\n" );
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document.write( "The explanation in words makes this look like a longer path to the answer than the formal algebra.  However, the numbers you need to work with are much simpler with this informal solution method.<br><BR>\n" );
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