document.write( "Question 2000: Hi All,\r
\n" ); document.write( "\n" ); document.write( "I have -3x + 6y = -12, I can workout how to get to x=0,y=-2,
\n" ); document.write( " but I'm lost on the x=3,y=-1/2. \r
\n" ); document.write( "\n" ); document.write( "Here goes\r
\n" ); document.write( "\n" ); document.write( "-3x + 6y = -12
\n" ); document.write( "6y = 3x -12 (take over the 3x to leave 6y)
\n" ); document.write( "y =6/3x - 2 (divide by 6 to get to y)
\n" ); document.write( "y = 2x - 2 (final answer)\r
\n" ); document.write( "\n" ); document.write( "When I enter x = 3, I get y = 4, not y = -1/2.\r
\n" ); document.write( "\n" ); document.write( "as\r
\n" ); document.write( "\n" ); document.write( "y = 2x -2 = 6 - 2 = 4\r
\n" ); document.write( "\n" ); document.write( "Why? (Ok its must be something I've done wrong, but what?)\r
\n" ); document.write( "\n" ); document.write( "Many thanks\r
\n" ); document.write( "\n" ); document.write( "Many thanks\r
\n" ); document.write( "\n" ); document.write( "Marcus
\n" ); document.write( "

Algebra.Com's Answer #811 by longjonsilver(2297)\"\" \"About 
You can put this solution on YOUR website!
after \"here goes\"...third line is wrong. It should be:\r
\n" ); document.write( "\n" ); document.write( "\"y+=+%283x%29%2F%286%29+-2%29\"
\n" ); document.write( "\"y+=+%28x%2F2%29+-2\"\r
\n" ); document.write( "\n" ); document.write( "so, put x=3 in... y=3/2 - 2 which is -1/2. Now correct :-)\r
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\n" ); document.write( "\n" ); document.write( "jon\r
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