document.write( "Question 1181125: Given: cos A = 3/5, tan B = 12/5, A is in Quadrant 1 and is in Quadrant 3
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document.write( "Find
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document.write( "1.Sin (A + B)
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document.write( "2.Sin (A - B)
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document.write( "3.Cos (A + B)
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document.write( "4.Cos (A - B)
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document.write( "5.Tan (A - B)
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document.write( "6.Tan ( A+ B) \n" );
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Algebra.Com's Answer #810963 by mananth(16946)![]() ![]() You can put this solution on YOUR website! cos A = 3/5, A is in Quadrant 1 \n" ); document.write( "sin A =4/5 , cos A = 3/5 , tan A =4/3\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "tan B = 12/5, quadrant IV\r \n" ); document.write( "\n" ); document.write( "tan B = -12/5, sin B = -12/13 , cos B = 5/13\r \n" ); document.write( "\n" ); document.write( "Sin (A + B) = sin(a)cos(b) + cos(a)sin(b) \n" ); document.write( " = (4/5)(5/13) +(3/5)(-12/13) \n" ); document.write( "= 20/65 - 36/65 \n" ); document.write( "-16/65\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "sin(A − B) = sin A cos B − cos A sin B\r \n" ); document.write( "\n" ); document.write( "=(4/5)(5/13) -(3/5)(-12/13) \n" ); document.write( "56/65\r \n" ); document.write( "\n" ); document.write( "cos(A + B) = cos A cos B − sin A sin B \n" ); document.write( "cos(A − B) = cos A cos B + sin A sin B \n" ); document.write( "sin(A + B) = sin A cos B + cos A sin B \r \n" ); document.write( "\n" ); document.write( "Plug values and continue\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |