document.write( "Question 1180953: Find the equation in standard form of the hyperbola whose foci are F1(−4√2, 0) and F2(4√2, 0), such that for any point on it, the absolute value of the difference of its distances from the foci is 8. \n" ); document.write( "
Algebra.Com's Answer #810944 by MathLover1(20850)\"\" \"About 
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You have the distance between the foci is \r
\n" ); document.write( "\n" ); document.write( "\"8sqrt%282%29+=+2c\" -> \"c+=4sqrt%282%29\"\r
\n" ); document.write( "\n" ); document.write( "A property of hyperbolas is that the absolute value of the difference of the distances from the foci is equal to the length of the transverse axis: \r
\n" ); document.write( "\n" ); document.write( "\"8+=+2a\" -> \"a+=+4\"\r
\n" ); document.write( "\n" ); document.write( "Another property is that \r
\n" ); document.write( "\n" ); document.write( "\"a%5E2+%2B+b%5E2+=+c%5E2+\"\r
\n" ); document.write( "\n" ); document.write( "from which you can find \"b\" (half the conjugate axis), \"b+=+4\". \r
\n" ); document.write( "\n" ); document.write( "Since the foci are on a horizontal line, your hyperbola is oriented \"horizontally\". \r
\n" ); document.write( "\n" ); document.write( "The \"center\" halfway between the foci, in this case at the \"origin\". \r
\n" ); document.write( "\n" ); document.write( "So the equation is \r
\n" ); document.write( "\n" ); document.write( "\"x%5E2%2Fa%5E2+-+y%5E2%2Fb%5E2+=+1+\"\r
\n" ); document.write( "\n" ); document.write( "with \"a+=+b+=+4\" in this case. \r
\n" ); document.write( "\n" ); document.write( "\"x%5E2%2F4%5E2+-+y%5E2%2F4%5E2+=+1+\"\r
\n" ); document.write( "\n" ); document.write( "\"x%5E2%2F16+-+y%5E2%2F16+=+1+\"\r
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