document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1181100>Question 1181100</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The Doe family is ready to fill their new swimming pool. It can be filled in 12 hours if they use their own water hose, and in 30 hours if they use Mr. Jones', their neighbor's water hose. How long will the Doe's take to fill their pool if the neighbor's hose is used along with their own?<BR>\n" );
document.write( "4 2/7 hours<BR>\n" );
document.write( "6 1/2 hours<BR>\n" );
document.write( "8 4/7 hours </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #810924 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13206)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=810924\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "Here is an alternative method for solving this kind of problem that many students like, because it avoids working with fractions.<br><BR>\n" );
document.write( "Consider the least common multiple of the two times given. LCM(12,30)=60.<br><BR>\n" );
document.write( "In 60 hours, the Doe hose could fill the pool 60/12=5 times; the Jones hose could fill the pool 60/30=2 times.<br><BR>\n" );
document.write( "So in 60 hours together the two hoses could fill the pool 5+2=7 times.<br><BR>\n" );
document.write( "That means together they can fill the one pool in 60/7 = 8 4/7 hours.<br><BR>\n" );
document.write( "ANSWER: 8 4/7 hours<br><BR>\n" );
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