document.write( "Question 1181096: The graph has an equation in the form of f(x) = a(1/2)^b(x+2)+k. What is the actual equation?\r
\n" );
document.write( "\n" );
document.write( "Please view the graph at:
\n" );
document.write( "https://docs.google.com/document/d/1Cl3HrcoR6jibNzxfDTIilS3imSplLY8nQUU0OpU9vLA/edit?usp=sharing \n" );
document.write( "
Algebra.Com's Answer #810916 by greenestamps(13200)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "f(x) = a(1/2)^b(x+2)+k \n" ); document.write( "NOTE: To make the form of the function absolutely clear, the whole exponent \"b(x+2)\" should be in parentheses: f(x) = a(1/2)^(b(x+2))+k \n" ); document.write( " \n" ); document.write( "Use the two given points and the horizontal asymptote to get three equations that can be solved to determine the constants a, b, and k. \n" ); document.write( "(1) horizontal asymptote: \n" ); document.write( "For large values of x, the decaying exponential goes to zero, making the function close to f(x)=k. Since the asymptote is y=4, we have k=4. \n" ); document.write( "(2) f(-2) = 1: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "(3) f(-3) = -8: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "a=-3; b=2; k=4 \n" ); document.write( "The function is \n" ); document.write( " \n" ); document.write( "A graph: \n" ); document.write( " \n" ); document.write( " |