document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1181029>Question 1181029</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A 3-inch diameter hole is drilled 6inches deep into the center and normal to the top face of brass cube 8 inches on the side. The hole is filled with lead. If a brass weighs 525lb/ft^3 and the lead weighs 705lb/ft^3. Find the total mass of the two metals </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #810889 by </B><A HREF=/tutors/aboutme.mpl?userid=htmentor><B>htmentor(1343)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=htmentor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=htmentor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=810889\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The mass of brass is equal to the volume of the cube minus the hole times the<BR>\n" );
document.write( "density of brass<BR>\n" );
document.write( "The mass of lead is equal to the volume of the hole times the density of lead<BR>\n" );
document.write( "The volume of the cube = 8^3 = 512 in^3<BR>\n" );
document.write( "The volume of the hole = pi*r^2*l = pi*(3/2)^2*6 = 41.412 in^3<BR>\n" );
document.write( "Convert the densities to lb/in^3. 1 ft^3 = 1728 in^3<BR>\n" );
document.write( "525 lb/ft^3 = 525/1728 = 0.30382 lb/in^3; 705 lb/ft^3 = 0.40799 lb/in^3<BR>\n" );
document.write( "Thus the mass of brass = (512 - 41.412)*0.30382 = 142.974 lb<BR>\n" );
document.write( "The mass of lead = 41.412*0.40799 = 16.896 lb </SPAN>\n" );
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