document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1181029>Question 1181029</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A 3-inch diameter hole is drilled 6inches deep into the center and normal to the top face of brass cube 8 inches on the side. The hole is filled with lead. If a brass weighs 525lb/ft^3 and the lead weighs 705lb/ft^3. Find the total mass of the two metals </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #810858 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=810858\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> mass in cylindrical hole = pi * r^2 * h * density of lead in ounce/cu.in<BR>\n" );
document.write( "Mass= Density * volume\r<BR>\n" );
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document.write( "1lb/cft = 0.009 ounces/cu. in<BR>\n" );
document.write( "705 lb/cft = 6.35 ounces / cu. in\r<BR>\n" );
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document.write( "pi*1.5^2 *6*6.35= 269 ounces\r<BR>\n" );
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document.write( "Now volume of remaining cube after drilling\r<BR>\n" );
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document.write( "8^3 -269= 243 in^3<BR>\n" );
document.write( "weight \r<BR>\n" );
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document.write( "243 * 4.86 =1181 ounces<BR>\n" );
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document.write( " </SPAN>\n" );
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