document.write( "Question 111135: The path of a falling object is given by the function s=-16t2+v0t+s0 where v0 represents the initial velocity in ft/sec and s0 represents the initial height in feet.
\n" ); document.write( "If a rock is thrown upward with an initial velocity of 64 feet per second from the top of a 25-foot building, write the height (s) equation using this information. Typing hint: Type t-squared as t^2
\n" ); document.write( "How high is the rock after 1 second?
\n" ); document.write( "After how many seconds will the graph reach maximum height?
\n" ); document.write( "What is the maximum height? \r
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Algebra.Com's Answer #81084 by solver91311(24713)\"\" \"About 
You can put this solution on YOUR website!
\"s=-16t%5E2%2Bv%5B0%5Dt%2Bs%5B0%5D\"
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\n" ); document.write( "\"s=-16t%5E2%2B64t%2B25\": substituting the values of \"v%5B0%5D=64+fps\" and \"s%5B0%5D=25feet\"
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\n" ); document.write( "After 1 second, \"s=-16%281%29%5E2%2B64%281%29%2B25=-16%2B64%2B25=73\"
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\n" ); document.write( "\"s=-16t%5E2%2B64t%2B25\" would graph as a parabola opening downward, and the maximum height would occur at the vertex of the parabola. The t-coordinate of the vertex is given by \"-b%2F2a=-64%2F%282%28-16%29%29=2\".
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\n" ); document.write( "\"s=-16%282%29%5E2%2B64%282%29%2B25=-64%2B128%2B25=89feet\"
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\n" ); document.write( "\"graph%28400%2C400%2C-0.5%2C6%2C-10%2C100%2C-16x%5E2%2B64x%2B25%2C25%29\"
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\n" ); document.write( "When interpreting the graph, remember that the x-axis is time, and the y-axis is distance. Notice that the graph crosses the y-axis at 25 feet because that is the value of \"s%5B0%5D\". Also, anything on the graph to the left of the y-axis is meaningless because that would represent negative time values, and anything below the x-axis represents something beneath the ground.
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