document.write( "Question 1180971: using the bionomial distribution find probabilities ??
\n" ); document.write( "3 success in 8 trails when p=0.4
\n" ); document.write( "2 failure in 6 trails when p=0.6
\n" ); document.write( "2 of fewer success in 9 trails when p=0.4
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Algebra.Com's Answer #810790 by greenestamps(13334)\"\" \"About 
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\n" ); document.write( "The calculation for binomial probability is well defined; you simply need to do the calculations. You can do that as easily as we can.

\n" ); document.write( "I will outline the calculation required for the first problem and leave the actual work for the rest of the problem to you.

\n" ); document.write( "(1) 3 successes in 8 trials with p=0.4....

\n" ); document.write( "(a) You need to choose 3 of the 8 trials to be the successful ones: C(8,3)
\n" ); document.write( "(b) The probability of each of the 3 successes is 0.4: (0.4)^3
\n" ); document.write( "(c) The probability of each of the 5 failures is 1-0.4=0.6: (0.6)^5

\n" ); document.write( "ANSWER: (C(8,3))*((0.4)^3)*((0.6)^5))

\n" ); document.write( "Use a calculator....

\n" ); document.write( "The same calculation with different numbers is required for the other two problems.

\n" ); document.write( "(2) 2 failures in 6 trials with p=0.6....

\n" ); document.write( "Two notes about this one.
\n" ); document.write( "(a) 2 failures in 6 trials means 4 successes.
\n" ); document.write( "(b) The p=0.6 must be assumed to be the probability of a success

\n" ); document.write( "(3) 2 or fewer successes in 9 trials with p=0.4

\n" ); document.write( "For this one you will need to do the calculation 3 times -- with 0, 1, or 2 successes -- and add the three probabilities.

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