document.write( "Question 1180947: A certain type of bacteria, given a favorable growth medium, doubles in population every 6.5 hours. Given that there were approximately 100 bacteria to start with, how many bacteria will there be after one and a half days? \n" ); document.write( "
Algebra.Com's Answer #810766 by ikleyn(52803)![]() ![]() You can put this solution on YOUR website! . \n" ); document.write( "A certain type of bacteria, given a favorable growth medium, doubles in population every 6.5 hours. \n" ); document.write( "Given that there were approximately 100 bacteria to start with, how many bacteria will there be \n" ); document.write( "after one and a half days? \n" ); document.write( "~~~~~~~~~~~~~~~~\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \r\n" ); document.write( "With the doubling peroiod of 6.5 hours and initial population of 100 bacteria,\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "the current population, as the function of time, is n(t) = 100*2^(t/6.5), where t is the time in hours.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "To find the population in 1.5 days = 1.5*24 = 36 hours, the fotmula is\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( " n(36 hours) = 100*2^(36/6.5).\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "Use your calculator.\r\n" ); document.write( "\r \n" ); document.write( "\n" ); document.write( "------------\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Solved.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Is everything clear to you in my explanation ?\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "If you still have questions, do not hesitate ask me.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "/////////////\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "To see many other similar and different solved problems on bacteria growth, look into the lesson\r \n" ); document.write( "\n" ); document.write( " - Bacteria growth problems \r \n" ); document.write( "\n" ); document.write( "in this site.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Also, you have this free of charge online textbook in ALGEBRA-I in this site\r \n" ); document.write( "\n" ); document.write( " - ALGEBRA-I - YOUR ONLINE TEXTBOOK.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The referred lesson is the part of this online textbook under the topic \"Logarithms\".\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Save the link to this online textbook together with its description\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Free of charge online textbook in ALGEBRA-I \n" ); document.write( "https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "to your archive and use it when it is needed.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |