document.write( "Question 1180948: 3. A sample of a radioactive isotope was found to be 40 mg 18 days ago and 5 mg today.\r
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Algebra.Com's Answer #810762 by ikleyn(52790)\"\" \"About 
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\n" ); document.write( "3. A sample of a radioactive isotope was found to be 40 mg 18 days ago and 5 mg today.
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document.write( "(a)  The ratio of the current mass to the initial mass is  \"5%2F40\" = \"1%2F8\" = \"1%2F2%5E3\".\r\n" );
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document.write( "     It means that 3 (three) half-lives passed from the beginning to the current moment.\r\n" );
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document.write( "     It means that 18 days comprize 3 half-lives.  Hence, one half-life is \"18%2F3\" = 6 days.     ANSWER\r\n" );
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document.write( "(b)  12 days from today comprise  12/6 = 2 half-lives;\r\n" );
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document.write( "     So, in 12 days after today, the remaining mass will be  \"5%2A%281%2F2%5E2%29\" = \"5%2F4\" = 1.25 milligrams.    ANSWER\r\n" );
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\n" ); document.write( "\n" ); document.write( "On radioactive decay,  see the lesson\r
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\n" ); document.write( "\n" ); document.write( "You will find many similar  (and different)  solved problems there.\r
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\n" ); document.write( "\n" ); document.write( "        Use this lesson as your handbook,  textbook,  guide,  tutorials, and  (free of charge)  home teacher.\r
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\n" ); document.write( "\n" ); document.write( "Also,  you have this free of charge online textbook in  ALGEBRA-I  in this site\r
\n" ); document.write( "\n" ); document.write( "    - ALGEBRA-I - YOUR ONLINE TEXTBOOK.\r
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\n" ); document.write( "\n" ); document.write( "The referred lesson is the part of this online textbook under the topic \"Logarithms\".\r
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\n" ); document.write( "\n" ); document.write( "Save the link to this online textbook together with its description\r
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\n" ); document.write( "\n" ); document.write( "Free of charge online textbook in ALGEBRA-I
\n" ); document.write( "https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson\r
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\n" ); document.write( "\n" ); document.write( "to your archive and use it when it is needed.\r
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