document.write( "Question 111108: Can you help me please? This application problem I can't figure out.\r
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document.write( "Julie and Eric row their boat (at a constant speed) 55 miles downstream for 5hrs,helped by the current. Rowing at the same rate,the trip back against the current takes 11 hours. Find the rate of the current. \n" );
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Algebra.Com's Answer #81076 by uma(370)![]() ![]() ![]() You can put this solution on YOUR website! Sure, I will help you.\r \n" ); document.write( "\n" ); document.write( "Let x mil/hr be the speed of the boat and y mil / hr be that of the current.\r \n" ); document.write( "\n" ); document.write( "Down stream they travelled 55 miles in 5 hrs\r \n" ); document.write( "\n" ); document.write( "==> their speed = distance/time\r \n" ); document.write( "\n" ); document.write( " = 55/5\r \n" ); document.write( "\n" ); document.write( " = 11 miles/hr\r \n" ); document.write( "\n" ); document.write( "Actually downstream the speed = speed of boat + speed of current\r \n" ); document.write( "\n" ); document.write( "==> x + y = 11 ---------------(1)\r \n" ); document.write( "\n" ); document.write( "Up stream they travelled 55 miles in 11 hrs \n" ); document.write( "==> their speed = distance/time \n" ); document.write( " = 55/11 \n" ); document.write( " = 5 miles/hr\r \n" ); document.write( "\n" ); document.write( "upstream the speed = speed of boat - speed of current \n" ); document.write( "==> x - y = 5 ---------------(2)\r \n" ); document.write( "\n" ); document.write( "(1) - (2) gives 2y = 6\r \n" ); document.write( "\n" ); document.write( "==> y = 6/2 \n" ); document.write( " = 3\r \n" ); document.write( "\n" ); document.write( "Thus the speed of the current = 3 miles/hr\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Good luck!!! \n" ); document.write( " |