document.write( "Question 111108: Can you help me please? This application problem I can't figure out.\r
\n" ); document.write( "\n" ); document.write( "Julie and Eric row their boat (at a constant speed) 55 miles downstream for 5hrs,helped by the current. Rowing at the same rate,the trip back against the current takes 11 hours. Find the rate of the current.
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Algebra.Com's Answer #81076 by uma(370)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "Let x mil/hr be the speed of the boat and y mil / hr be that of the current.\r
\n" ); document.write( "\n" ); document.write( "Down stream they travelled 55 miles in 5 hrs\r
\n" ); document.write( "\n" ); document.write( "==> their speed = distance/time\r
\n" ); document.write( "\n" ); document.write( " = 55/5\r
\n" ); document.write( "\n" ); document.write( " = 11 miles/hr\r
\n" ); document.write( "\n" ); document.write( "Actually downstream the speed = speed of boat + speed of current\r
\n" ); document.write( "\n" ); document.write( "==> x + y = 11 ---------------(1)\r
\n" ); document.write( "\n" ); document.write( "Up stream they travelled 55 miles in 11 hrs
\n" ); document.write( "==> their speed = distance/time
\n" ); document.write( " = 55/11
\n" ); document.write( " = 5 miles/hr\r
\n" ); document.write( "\n" ); document.write( "upstream the speed = speed of boat - speed of current
\n" ); document.write( "==> x - y = 5 ---------------(2)\r
\n" ); document.write( "\n" ); document.write( "(1) - (2) gives 2y = 6\r
\n" ); document.write( "\n" ); document.write( "==> y = 6/2
\n" ); document.write( " = 3\r
\n" ); document.write( "\n" ); document.write( "Thus the speed of the current = 3 miles/hr\r
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\n" ); document.write( "\n" ); document.write( "Good luck!!!
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