document.write( "Question 1180867: A regular hexagon A has the midpoints of its edge joined to form a smaller hexagon B, and this process is repeated by joining the midpoints of the edges of B to get a third hexagon C. What is the ratio of the area of C to the area of A \n" ); document.write( "
Algebra.Com's Answer #810696 by greenestamps(13200)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "Make a sketch and draw segments from the centers of the hexagons to each vertex of both hexagons. \n" ); document.write( "Neighboring segments, along with the sides of hexagon A, form 30-60-90 degree triangles. So in those triangles, the length of a segment to the vertex of hexagon A and the length of a segment to the vertex of hexagon B are in the ratio 2:sqrt(3) (hypotenuse and long leg of a 30-60-90 right triangle). \n" ); document.write( "Those segments are corresponding parts of hexagon A and hexagon B; the ratio of the areas of the two hexagons is the square of the ratio of the lengths of the corresponding sides. \n" ); document.write( "So the ratio of the areas of hexagons A and B is 4:3. \n" ); document.write( "Of course you will have the same ratio of areas when you construct hexagon C using the midpoints of the sides of hexagon B. \n" ); document.write( "So when hexagons are inscribed in hexagons as described in this problem, the area of each hexagon is 3/4 of the area of the previous hexagon. \n" ); document.write( "So the ratio of the area of hexagon C to the area of hexagon A is (3/4)^2 = 9/16, or 9:16. \n" ); document.write( " \n" ); document.write( " |