document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1180818>Question 1180818</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 2) If the readings on thermometers are normally distributed with a mean of 0o C  and  a standard deviation of 1.00o   C.<BR>\n" );
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document.write( "a) If 5 % of thermometers are rejected because  they have readings that are too low, but the rest are accepted, what is the reading that separates the rejected thermometers from the others.<BR>\n" );
document.write( "b) What is the 90th percentile?<BR>\n" );
document.write( "c) If 3 % of thermometers are rejected  because they have readings that are too high and 4 % are rejected because they are too low, what are the cutoff values separating the rejected thermometers from the others? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #810685 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=810685\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> a. z(0.05)=-1.645, so temp is -1.645 C.<BR>\n" );
document.write( "b. 90th percentile is +1.282 C.<BR>\n" );
document.write( "z(0.04)=-1.75 C. and z(0.97)=+1.88 C.<BR>\n" );
document.write( "Those are the lower and upper limits respectively. <BR>\n" );
document.write( "use 2nd VARS3invnorm(0.05,0,1)ENTER, where 0.05 would be the 5th percentile, the 0, 1 are mean and sd of the standard normal distribution. </SPAN>\n" );
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