document.write( "Question 1180881: A boat can be rowed at 4 times the speed of the current. If the boater in travel 18 miles upstream in six hours and 10 miles downstream in two hours, how fast in miles per hour can the boat be rowed? Show your work \n" ); document.write( "
Algebra.Com's Answer #810680 by ikleyn(52797)![]() ![]() You can put this solution on YOUR website! . \n" ); document.write( " \r\n" ); document.write( "\r\n" ); document.write( "If the boat can be rowed at 4 times the speed of the current, then its speed upstream is 4r - r = 3r,\r\n" ); document.write( "where \"r\" is the rate of the current.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "Then for \"r\" you have this distance equation\r\n" ); document.write( "\r\n" ); document.write( " 6 hours * 3r mph = 18 miles, \r\n" ); document.write( "\r\n" ); document.write( "which gives the ANSWER r = 18/(6*3) = 1 mph for the rate of the current and 4*1 = 4 mph for the rate of the boat in still water.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "In this problem, ONLY ONE condition is necessary: EITHER for upstream travel OR for downstream travel.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "To have these two conditions is UNNECESSARY and EXCESSIVE LUXURY in this problem.\r\n" ); document.write( "\r \n" ); document.write( "\n" ); document.write( "Solved, answered and explained.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |