document.write( "Question 1180858: A farmer has two tractors P and Q. Tractor P, working alone, can plough a piece of land in 5 hours while tractor Q would take 1.6667 hours less than tractor P.
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document.write( " (a) Determine the time the two tractors ploughing together,would take to complete the work. (3 marks)
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document.write( "(b) One day, the tractors started to plough the piece of land together. After 40 minutes,tractor P broke down but Q continued alone and completed the work.
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document.write( "Calculate the total time taken to plough the piece of land that day. (4 marks)
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document.write( "(c) In another season, the farmer hired an additional tractor R to assist P and Q which retained the same rate of working as before. The three tractors took I hour 12 minutes to plough the same piece of land. The owner of tractor R was paid some money proportional to the work done by the tractor.
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document.write( "If the total work was valued at ksh 20000 , find the amount of money paid to the owner of tractor R. \n" );
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Algebra.Com's Answer #810669 by greenestamps(13200)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "The other tutor answered only one question because of an unreasonable interpretation of the rule \"one question per post\". \n" ); document.write( "Your post is not several separate unrelated questions; it is a single problem with three related questions. Posting the three questions as separate posts would make no sense; they NEED TO BE posted together. \n" ); document.write( "The other tutor also misread the information in the first part of the problem and so gave a solution to a different problem. \n" ); document.write( "------------------------------------------------------------------------- \n" ); document.write( "(a) Tractor P can do the job alone in 5 hours; tractor Q can do it in (5-1.6667)=3.333 hours. So P can do (1/5) of the job in 1 hour and Q can do (1/3.333) = 3/10 of the job in 1 hour. \n" ); document.write( "Working together then, the two tractors can do 1/5+3/10 = 1/2 of the job in 1 hour; so they can do the job together is 1/(1/2) = 2 hours. \n" ); document.write( "ANSWER: 2 hours \n" ); document.write( "(b) P and Q work together for 40 minutes (2/3 of an hour). Since together they can do 1/2 of the job in one hour, they do \n" ); document.write( "So 2/3 of the job remains to be done. The additional time it takes Q to finish the job, working at 3/10 of the job per hour, is \n" ); document.write( "That's an additional 2 2/9 hours, or 2 hours 13 1/3 minutes to finish the job. \n" ); document.write( "ANSWER: 40 minutes plus 2 hours 13 1/3 minutes = 2 hours 53 1/3 minutes. \n" ); document.write( "(c) The three tractors together take 1 hour 12 minutes to finish the job together, or 6/5 hours. That means they do 5/6 of the job together in 1 hour. \n" ); document.write( "P and Q together do 1/2 of the job in 1 hour. So tractor R in 1 hour does \n" ); document.write( "The three tractors together finished the job in 6/5 hours, so the fraction of the job done by tractor R was \n" ); document.write( "So the amount to be paid to the owner of tractor R is 2/5 of the total of ksh 20000, or ksh 8000. \n" ); document.write( "ANSWER: ksh 8000 \n" ); document.write( " \n" ); document.write( " |