document.write( "Question 1180829: Find x coordinate of the point on the graph y=square root of x+8 where the tangent line is parallel to the secant line that cuts the curve at x =-8 and x=7. \n" ); document.write( "
Algebra.Com's Answer #810633 by greenestamps(13200)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "Evaluate the function at x=-8 and x=7: f(-8)=0; f(7)=sqrt(15). \n" ); document.write( "Find the equation of the secant: (-8,0) to (7,sqrt(15)) \n" ); document.write( "slope = sqrt(15)/(7-(-8)) = sqrt(15)/15 \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Graph the function and the secant: \n" ); document.write( " \n" ); document.write( "Find the derivative of the function: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Find the x value where the slope of the tangent is the same as the slope of the secant. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Graph the line with slope sqrt(15)/15 touching y=sqrt(x+8) at x=-17/4 and observe that it is parallel to the secant: \n" ); document.write( "Graph the function and the secant: \n" ); document.write( " \n" ); document.write( "ANSWER: x = -17/4. \n" ); document.write( "At x=-17/4, the tangent to y=sqrt(x+8) is parallel to the secant through x=-8 and x=7. \n" ); document.write( " \n" ); document.write( " |