document.write( "Question 1180814: A chemist has three different acid solutions. The first acid solution contains 20% acid the second it contains 30% and the third contains 75%. They want to use all three solutions to obtain a mixture of 96 L containing 45% acid using two times as much of the 75% solution as the 30% solution. How many liters of each solution should be used. \n" ); document.write( "
Algebra.Com's Answer #810596 by josgarithmetic(39617)![]() ![]() ![]() You can put this solution on YOUR website! \r\n" ); document.write( "CONC % VOLUME PURE\r\n" ); document.write( " 20 96-3v 0.2(96-3v)\r\n" ); document.write( " 30 v 0.3v\r\n" ); document.write( " 75 2v 0.75*2v\r\n" ); document.write( "-----------------------------------\r\n" ); document.write( " 45 96 L 43.2\r\n" ); document.write( " \n" ); document.write( "You can see what equation to make from this. \n" ); document.write( " |