document.write( "Question 1180794: THE SCORES OF AN ENTRANCE TEST FOR HIGH SCHOOL PASS-OUTS IN A PARTICULAR YEAR WERE BELL-SHAPED. THE MEAN AND STANDARD DEVIATION WERE 490 AND 100 RESPECTIVELY.\r
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document.write( "WHAT percentage of the students scored between 390 and 590 on this test?
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document.write( "what is the area under the normal distribution curve between z= -1.3 and z= 0.99?
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document.write( "for a specific confidence interval,what will happen to the margin of error if the sample size is larger?
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document.write( "a.it becomes smaller
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document.write( "b.it becomes larger
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document.write( "c. equal
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document.write( "d. the same\r
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document.write( "when a 99% confidence interval is calculated instead of a 95% confidence interval with n being the same, the margin of error will be.\r
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document.write( "a.smaller
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document.write( "b.larger
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document.write( "c. the same
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document.write( "d. it cannot be determine \n" );
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Algebra.Com's Answer #810585 by ewatrrr(24785) You can put this solution on YOUR website! \r\n" ); document.write( "Hi\r\n" ); document.write( "Normal Distribution: µ = 490 and σ = 100 \r\n" ); document.write( "Using TI or similarly an inexpensive calculator like a Casio fx-115 ES plus\r\n" ); document.write( "Continuous curve\r\n" ); document.write( "\r\n" ); document.write( "P(390 > x > 590)= normalcdf(390, 590, 490, 100) = .6827 0r 68% (2 decimal places)\r\n" ); document.write( "Keisan Online Calculator\r\n" ); document.write( "\n" ); document.write( " |