document.write( "Question 1180790: THE SCORES OF AN ENTRANCE TEST FOR HIGH SCHOOL PASS-OUTS IN A PARTICULAR YEAR WERE BELL-SHAPED. THE MEAN AND STANDARD DEVIATION WERE 490 AND 100 RESPECTIVELY.\r
\n" ); document.write( "\n" ); document.write( "WHAT PERCENTAGE OF THE STUDENTS SCORED BETWEEN 390 AND 590 ON THIS TEST?
\n" ); document.write( "A.2.35% B.13.5% C.34% D.68%\r
\n" ); document.write( "\n" ); document.write( "WHAT IS THE AREA UNDER THE NORMAL DISTRIBUTION CURVE BETWEEN Z= -1.3 AND Z=0.99? \n" ); document.write( "
Algebra.Com's Answer #810582 by ewatrrr(24785)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "Hi\r\n" );
document.write( "Normal Distribution:  µ = 490 and σ = 100 \r\n" );
document.write( "Using TI or similarly an inexpensive calculator like a Casio fx-115 ES plus\r\n" );
document.write( "Continuous curve\r\n" );
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document.write( "P(390 > x > 590)= normalcdf(390, 590, 490, 100) = .6827  0r 68% (2 decimal places)\r\n" );
document.write( "Keisan Online Calculator\r\n" );
document.write( "   .\r\n" );
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document.write( "P(-1.3 > z > 8.99)= normalcdf(-1.3, 8.99, 0, 1) = .90 (2 decimal places)\r\n" );
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document.write( "Important You feel comfortable using Your calculator.\r\n" );
document.write( "Wish You the Best in your Studies.\r\n" );
document.write( "standard Normal Curve:  µ = 0 and σ = 1\r\n" );
document.write( "various z-values given \r\n" );
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