document.write( "Question 1180791: Please help me solve this question.\r
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document.write( "Solve each of the following for 0 <= theta <= 360 degrees
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document.write( "3sin^2 theta + 2sin theta = 0 \n" );
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Algebra.Com's Answer #810576 by Theo(13342)![]() ![]() You can put this solution on YOUR website! equation is 3sin^2(theta) + 2sin(theta) = 0 \n" ); document.write( "factor out sin(theta) to get: \n" ); document.write( "sin(theta) * (3sin(theta) + 2) = 0 \n" ); document.write( "this is true when sin(theta) = 0 or 3sin(theta) + 2 = 0 \n" ); document.write( "solve for sin(theta) to get: \n" ); document.write( "sin(theta) = 0 or sin(theta) = -2/3. \n" ); document.write( "the reference angle (equivalent angle in the first quadrant) will be: \n" ); document.write( "theta = arcsin(0) = 0 degrees. \n" ); document.write( "theta = arcsin(2/3) = 41.8103149 degrees. \n" ); document.write( "note that the trig function is always positive in the first quadrant. \n" ); document.write( "sin(theta) is 0 when theta = 0 or 180 degrees or 360 degrees. \n" ); document.write( "sin(theta) is negative in the third and fourth quadrants. \n" ); document.write( "the reference angle of 41.8103149 in the third and fourth quadrant is found as follows: \n" ); document.write( "third quadrant = 41.8103149 + 180 = 221.8103149 degrees. \n" ); document.write( "fourth quadrant = 360 - 41.8103149 = 318.1896851 degrees. \n" ); document.write( "your angles that satisfy the equation of 3sin^2(theta) + 2sin(theta) = 0 are: \n" ); document.write( "0,180,360 degrees. \n" ); document.write( "221.8103149, 318.1896851 degrees. \n" ); document.write( "a graph of the equation is shown below:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " ![]() \n" ); document.write( " \n" ); document.write( " |