document.write( "Question 1180772: There are three consecutive even integers. If twice the first integer added to the third is 268,246 find all three integers. \n" ); document.write( "
Algebra.Com's Answer #810561 by greenestamps(13203)\"\" \"About 
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\n" ); document.write( "While it is often the case in problems with consecutive even integers that using x-2, x, and x+2 for the three integers makes the algebra needed to solve the problem easier, it does not look that way for this problem.

\n" ); document.write( "A quick mental solution could go like this:

\n" ); document.write( "The third integer is 4 more than the first; so if the sum of the third and twice the first is 268,246 then three times the first is 268,246-4=268,242. So the smallest of the integers is 268,242/3 = 89414.

\n" ); document.write( "ANSWERS: 89,414; 89,416; and 89,418

\n" ); document.write( "The same solution using formal algebra would look like this:

\n" ); document.write( "2(x)+(x+4) = 268246
\n" ); document.write( "3x+4 = 268246
\n" ); document.write( "3x=268242
\n" ); document.write( "x=268242/3 = 89414

\n" ); document.write( "89414, 89416, and 89418

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