document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1180731>Question 1180731</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Linda needs 10 gallons of solution that is 60% antifreeze. She has a solution <BR>\n" );
document.write( "that is 90% antifreeze and another that is 50% antifreeze. How much of each <BR>\n" );
document.write( "should she use? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #810504 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13200)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=810504\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "If a formal algebraic solution is not required, here is a fast and easy path to solving any two-part mixture problem like this.<br><BR>\n" );
document.write( "(1) The target 60% is 10/40=1/4 of the way from 50% to 90%.  (Picture the three percentages 50, 60, and 90 on a number line, if it helps.  60 is 10/40 = 1/4 of the way from 50 to 90.)<BR>\n" );
document.write( "(2) That means 1/4 of the 10-gallon mixture should be the 90% antifreeze.<br><BR>\n" );
document.write( "ANSWER: 1/4 of 10 gallons, of 2.5 gallons, of the 90% antifreeze, and the other 7.5 gallons of 50% antifreeze.<br><BR>\n" );
document.write( "CHECK:<BR>\n" );
document.write( ".50(7.5)+.90(2.5)=3.75+2.25=6<BR>\n" );
document.write( ".60(10)=6<br><BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );