document.write( "Question 16559: 2x^3-x^2-15x \n" ); document.write( "
Algebra.Com's Answer #8105 by rapaljer(4671)\"\" \"About 
You can put this solution on YOUR website!
First take out the common factor which is x:
\n" ); document.write( "\"2x%5E3-x%5E2-15x\"\r
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\n" ); document.write( "\n" ); document.write( "\"x%282x%5E2+-+x+-15%29\"\r
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\n" ); document.write( "\n" ); document.write( "Next, try to factor the trinomial into the product of two binomials, beginning with the \"2x%5E2\". The only way to break this down is to say 2x *x. The signs will be opposite, since the last term is a -15.\r
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\n" ); document.write( "\n" ); document.write( "\"x%282x%2B+_____%29%2A%28x-_____%29\"\r
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\n" ); document.write( "\n" ); document.write( "Next, you need to find a combination of -15, what times what will come out to -15 in such a way that the outer times outer terms will subtract and give you a -1x for the middle term. The combination that works is 5 times -3, as follows:\r
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\n" ); document.write( "\n" ); document.write( "\"x%282x%2B5%29%2A%28x-3%29+\", where the outer times outer is -6x and the inner times inner is +5x, for a total of -1x. That should do it:\r
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\n" ); document.write( "\n" ); document.write( "\"x%282x%2B5%29%2A%28x-3%29+\"\r
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\n" ); document.write( "\n" ); document.write( "R^2 at SCC
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