document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=111021>Question 111021</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I dont know how to set up these word problems...<BR>\n" );
document.write( "[how come they dont have a section for word problems ? O__O]\r<BR>\n" );
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document.write( "Find three consecutive odd integers such that the sum of the two least integers is 11 more than the greatest integer..\r<BR>\n" );
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document.write( "A rectangular park was 15m(meters) longer than it was wide. When a border of bushes 0.5m(meters) wide was planted around the edges of the park, the area of the park increased by 56m2(meters squared). Find the original dimensions of the park.\r<BR>\n" );
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document.write( "Marla has 3 dimes and half as many nickels as pennies. If her coins are worth 50cents in all, how many nickels does she have?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #81048 by </B><A HREF=/tutors/aboutme.mpl?userid=oberobic><B>oberobic(2304)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=oberobic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=81048\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> I cannot answer your question about a special word problem section. That is the Webmaster's area.\r<BR>\n" );
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document.write( "As a volunteer tutor, I can say that I am not inclined to take on answering a question that has 3 questions embedded in it. I might have time to answer 1 or 2, but perhaps not all 3. Also, by posting 3 questions, you could get lucky and have 3 tutors work in parallel to give you the 3 answers in 1/3 the time.\r<BR>\n" );
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document.write( "As to setting up the problems:\r<BR>\n" );
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document.write( "1) The consecutive integers would be x, x+1, and x+2. And we are told that <BR>\n" );
document.write( "x + (x+1) is 11 more than x+2. So,<BR>\n" );
document.write( "2x+1=x+2+11<BR>\n" );
document.write( "x=12.\r<BR>\n" );
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document.write( "2) A rectangule has area A=w*l, where w=width, l=length. <BR>\n" );
document.write( "We are told length is 15m more than w, so we could say l = w+15, or l-15=w.<BR>\n" );
document.write( "That means the original area A = w(w+15). We don't know what A is though.<BR>\n" );
document.write( "But the 0.5m row of bushes, means the length is increased by 1m and the width is increased by 1m (.5 is added on all sides). When that happens, A is increased by 56.<BR>\n" );
document.write( "Letting B = new area, the equation is<BR>\n" );
document.write( "B = (w+1)(w+15+1)<BR>\n" );
document.write( "A = w(w+15)<BR>\n" );
document.write( "B = A +56<BR>\n" );
document.write( "So...<BR>\n" );
document.write( "(w+1)(w+16) = w(w+15)+56.\r<BR>\n" );
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document.write( "3) With money problems, you have to keep track of the count as well as the value of the coins involved. Note that we can call the number of dimes d and the value, in cents, will be 10d. Likewise, nickels can be called n and their value is 5n. Pennies are p and have value p (or 1p, but the 1 is superfluous).\r<BR>\n" );
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document.write( "The total number of coins will be d+n+p. Their value will be 10d+5n+p.<BR>\n" );
document.write( "We know 10d+5n+p=50 cents. We also know the number of dimes is 3, so we can say<BR>\n" );
document.write( "30+5n+p=50. Subtracting 30 from both sides, we have 5n+p=20.\r<BR>\n" );
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document.write( "We are told she has half as many nickels as pennies. That means, if we have 2 pennies, we have 1 nickel; 4 pennies, 2 nickels; 6 pennies, 3 nickels; 8 pennies, 4 nickels; etc.\r<BR>\n" );
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document.write( "In all cases, the relationship is p=2n.\r<BR>\n" );
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document.write( "That means<BR>\n" );
document.write( "5n+2n=20\r<BR>\n" );
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document.write( "7n = 20, which presents us with a problem. 7 does not go into 20 an even number of times, so there is no solution. </SPAN>\n" );
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