document.write( "Question 1180674: Alan takes 6 days less than Bob to finisha task at work. If both Alan and Bob worktogether, they can finish the work in 4 days. Findthe time that Bob would take to finish the workby himself. \n" ); document.write( "
Algebra.Com's Answer #810411 by mananth(16946)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "Alan takes 6 days less than Bob to finish task at work. \r
\n" ); document.write( "\n" ); document.write( "let Bob take x days to finish the job alone
\n" ); document.write( "Bob does 1/x of thejob in 1 day
\n" ); document.write( "alan does 1/(x-6) of the job in 1 day
\n" ); document.write( "Alan will take x-6 days to finish the job alone\r
\n" ); document.write( "\n" ); document.write( "both Alan and Bob work together, they can finish the work in 4 days\r
\n" ); document.write( "\n" ); document.write( "Together they do 1/4 of the job in 1 day
\n" ); document.write( "1/x + 1/(x-6) = 1/4\r
\n" ); document.write( "\n" ); document.write( "Multiply the terms by x(x-6)*4\r
\n" ); document.write( "\n" ); document.write( "4(x-6) +4x = x(x-6)\r
\n" ); document.write( "\n" ); document.write( "4x-24 +4x= x^2-6x\r
\n" ); document.write( "\n" ); document.write( "x^2-14x+24=0
\n" ); document.write( "(x-12)(x-2)=0\r
\n" ); document.write( "\n" ); document.write( "x=12 OR 2
\n" ); document.write( "2 is not possible\r
\n" ); document.write( "\n" ); document.write( "Bob takes 12 days alone\r
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