document.write( "Question 1180633: Studies have shown that 400 people attend a high school basketball game when the admission price is $30 in the championship game, admission prices will increase for every $0.25 increase, 20 fewer people will attend. At what ticket will the revenue be maximized? \n" ); document.write( "
Algebra.Com's Answer #810405 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! I think you mean 2 fewer people, not 20, because if the ticket sales are $30.25 and 380 people attend, one will be losing money, compared to 400 and $30. \n" ); document.write( "Let x is number of $0.25 increase and multiples of 2 people. \n" ); document.write( "(400-x)(($30+0.25x) \n" ); document.write( "=12000-30x+100x-5x^2 \n" ); document.write( "the maximum is at x=-b/2a for this negative quadratic of -5x^2+70x+12000 \n" ); document.write( "this is x=70/10=7 \n" ); document.write( "so at $31.75 (7*$0.25-$1.75) and 386 people (400-7*2) \n" ); document.write( "there is a maximum, or $12,255.50 \n" ); document.write( " |