document.write( "Question 1180640: Write the complex number 3 + i sqrt 3 in its polar form: (r, theta).\r
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #810371 by MathLover1(20850)\"\" \"About 
You can put this solution on YOUR website!
\r
\n" ); document.write( "\n" ); document.write( "the complex number \"3+%2B+i%2Asqrt%283+%29\" in its polar form: (\"r\", \"theta\")\r
\n" ); document.write( "\n" ); document.write( "the complex number \"a+%2B+b%2Ai\" \r
\n" ); document.write( "\n" ); document.write( "in your case \"3+%2B+i%2Asqrt%283+%29\" , \"a=3\" and \"b=sqrt%283+%29\"\r
\n" ); document.write( "\n" ); document.write( "then \r
\n" ); document.write( "\n" ); document.write( "\"r=sqrt%28a%5E2%2Bb%5E2%29\"
\n" ); document.write( "\"r=sqrt%283%5E2%2B%28sqrt%283+%29%29%5E2%29\"
\n" ); document.write( "\"r=sqrt%289%2B3+%29\"
\n" ); document.write( "\"r=sqrt%2812+%29\"
\n" ); document.write( "\"r=sqrt%284%2A3+%29\"
\n" ); document.write( "\"r=2sqrt%283+%29\"\r
\n" ); document.write( "\n" ); document.write( "\"theta=tan%5E-1%28a%2Fb%29\"
\n" ); document.write( "\"theta=tan%5E-1%283%2Fsqrt%283+%29%29\"
\n" ); document.write( "\"theta=pi%2F6\"\r
\n" ); document.write( "\n" ); document.write( " polar form:\r
\n" ); document.write( "\n" ); document.write( "(\"2sqrt%283%29\" , \"+pi%2F6\")\r
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );