document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=111052>Question 111052</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help!  Solve the following exponential equation:\r<BR>\n" );
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document.write( "26 over(/)1-2e^6x = 50\r<BR>\n" );
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document.write( "I tried multiplying the denominator on the left & right, and dividing by the 50 to get this far:  26/50 = 1-2e^6x\r<BR>\n" );
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document.write( "I tried subtracting the one and multiplying the -2, but I wound up with Ln48/50 = 6x.  My answers to that are wrong.  What am I missing?  How do you do this problem if I'm wrong?   </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #81036 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=81036\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> first step looks good and part of the second step\r<BR>\n" );
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document.write( "you should be dividing the -2 to get ln(12/50)=6x </SPAN>\n" );
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