document.write( "Question 1180609: A cone and a hemisphere of equal surface area each
\n" ); document.write( "have a 3-inch radius. What is the height Of the
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Algebra.Com's Answer #810327 by MathLover1(20850)\"\" \"About 
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\r
\n" ); document.write( "\n" ); document.write( "and a hemisphere of equal surface area each have a 3-inch radius. what is the height of the cone?\r
\n" ); document.write( "\n" ); document.write( "SA = pi*r^2 + pi*rl\r
\n" ); document.write( "\n" ); document.write( "Where,
\n" ); document.write( "r is the radius
\n" ); document.write( "h is the height
\n" ); document.write( "l is the slant height\r
\n" ); document.write( "\n" ); document.write( "given: \"r=3\"\r
\n" ); document.write( "\n" ); document.write( "\"SA+=+pi%2A3%5E2+%2B+pi%2A3%2Al\"
\n" ); document.write( "\"SA+=+9pi+%2B+3pi%2Al\"...........eq.1\r
\n" ); document.write( "\n" ); document.write( "surface area of a hemisphere SA = 3pi*r^2 \r
\n" ); document.write( "\n" ); document.write( "given: \"r=3\"\r
\n" ); document.write( "\n" ); document.write( " \"SA+=+3pi%2A3%5E2\"
\n" ); document.write( "\"SA+=+27pi\"..........eq.2\r
\n" ); document.write( "\n" ); document.write( "from eq.1 and eq.2 we have\r
\n" ); document.write( "\n" ); document.write( "\"9pi+%2B+3pi%2Al=27pi\"...divide by \"3\"\r
\n" ); document.write( "\n" ); document.write( "\"3pi+%2B+pi%2Al=9pi\"\r
\n" ); document.write( "\n" ); document.write( "\"l=9pi-3pi\"\r
\n" ); document.write( "\n" ); document.write( "\"l=6pi%2F+pi\"\r
\n" ); document.write( "\n" ); document.write( "\"l=6\"-> slant height\r
\n" ); document.write( "\n" ); document.write( "the height of the cone will be\r
\n" ); document.write( "\n" ); document.write( "\"h=sqrt%286%5E2-3%5E2%29\"\r
\n" ); document.write( "\n" ); document.write( "\"h=sqrt%2836-9%29\"\r
\n" ); document.write( "\n" ); document.write( "\"h=sqrt%2825%29\"\r
\n" ); document.write( "\n" ); document.write( "\"h=5\"\r
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\n" ); document.write( "\n" ); document.write( " the height of the cone is \"5in\"\r
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