document.write( "Question 1180565: function: y= x^4-8x^3-16x+5
\n" ); document.write( "a. Identify range
\n" ); document.write( "b. find x-intercept (you can solve this using the intermediate value theorem to estimate where the roots will be, I'm just not sure how to do that exactly)
\n" ); document.write( "c. find critical numbers
\n" ); document.write( "d. points of extreme with the first derivative test for the interval of increasing and decreasing testing
\n" ); document.write( "- please show the work, I did some work on my own but I think I messed up in some steps. thank you very much.
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Algebra.Com's Answer #810322 by Boreal(15235)\"\" \"About 
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I would graph it first. Clearly +oo is the upper bound
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\n" ); document.write( "We know that when x=0 y=5, and as x increases from 0, the function will be decreasing, since subtracting the cube of a small positive number and the first power of a small positive number will both be larger than the adding the fourth power of that number.
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\n" ); document.write( "So one root will be between 0 and 1, closer to 0
\n" ); document.write( "when x=8, the x^4 and -8x^3 terms will cancel, making the function -123. Therefore, the next root will be somewhat larger than 8 and well below 9 (closer to 8).
\n" ); document.write( "The other two roots will be complex.
\n" ); document.write( "The critical values are at x=0.2996 and x=8.227. The function is continuous.
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\n" ); document.write( "The derivative is y'=4x^3-24x^2-16
\n" ); document.write( "set that equal to 0 and divide by 4, and the is x^3-6x^2-4=0
\n" ); document.write( "this is negative when x=6 and positive when x=7, so the local minimum is when x is in between those two points.
\n" ); document.write( "x=6.11
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\n" ); document.write( "So the range is (-523.8679, +oo)
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