document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=482220>Question 482220</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Jason has 50 coins, all in 5 and 1 peso coins, amounting to Php 130.00. How many 5 peso coin does he have?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #810280 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13200)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=810280\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "Algebraically....<br><BR>\n" );
document.write( "x+y=50  the number of coins is 50<BR>\n" );
document.write( "5x+1y=130  the value of the coins is 130 pesos<br><BR>\n" );
document.write( "The difference between the two equations is 4x=80, leading to x=20; that makes y=50-20=30<br><BR>\n" );
document.write( "ANSWER: 20 5-peso coins and 30 1-peso coins<br><BR>\n" );
document.write( "CHECK: 20(5)+30(1)=100+30=130<br><BR>\n" );
document.write( "Informally (if an algebraic solution is not required, and if the speed of getting the answer is important)....<br><BR>\n" );
document.write( "(1) imagine starting with all 50 coins being 1-peso coins; that would make the total 50 pesos, which is 80 pesos short of the actual total.<BR>\n" );
document.write( "(2) exchanging a 1-peso coin for a 5-peso coin keeps the total number of coins the same but increases the total value by 5-1=4 pesos.<BR>\n" );
document.write( "(3) 80/4 means there have to be 20 5-peso coins; and that means 30 1-peso coins<br><BR>\n" );
document.write( "The words of explanation make this informal solution longer than the formal algebraic solution.  But without all the words, here are the complete calculations for this method:<br><BR>\n" );
document.write( "50(1)=50<BR>\n" );
document.write( "130-50=80<BR>\n" );
document.write( "80/4=20<BR>\n" );
document.write( "50-20=30<br><BR>\n" );
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