document.write( "Question 1180546: Use the quadratic formula to determine, accurate to one decimal place, the roots, if they exist, for each quadratic relation. \r
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document.write( "a) y = 2x2 + 3x + 1 \r
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document.write( "b) y = x2 - 3x + 5 \r
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document.write( "c) y = x2 + x - 5 \r
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document.write( "d) y = - 9x2 - 6x + 1 \n" );
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Algebra.Com's Answer #810255 by mananth(16946)![]() ![]() You can put this solution on YOUR website! 2x2 + 3x + 1=0\r \n" ); document.write( "\n" ); document.write( "comparing with ax^2 +bx +c =0\r \n" ); document.write( "\n" ); document.write( "using the Quadratic Formula where \n" ); document.write( "a = 2, b = 3, and c = 1\r \n" ); document.write( "\n" ); document.write( "b^2-4ac= 9 + -8 \n" ); document.write( "b^2-4ac= 1 \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "substitute the values in the formula \n" ); document.write( " \n" ); document.write( "x1=( -3 + 1 )/ 4 \n" ); document.write( "x1= -0.5 \n" ); document.write( "x2=( -3 -1 ) / 4 \n" ); document.write( "x2= -1 \r \n" ); document.write( "\n" ); document.write( "Now you know thesteps \n" ); document.write( "solve the rest of them\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |