document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1180492>Question 1180492</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the equation of the line perpendicular to y = x -2 that passes through the point (0,4). </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #810177 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=810177\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the perpendicular line will have a slope that is the negative reciprocal of the slope of the line that it is perpendicular to.\r<BR>\n" );
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document.write( "the line that it is perpendicular to is y = x - 2.\r<BR>\n" );
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document.write( "the slope of that line is 1.\r<BR>\n" );
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document.write( "the negative reciprocal of that slope is -1/1 = -1.<BR>\n" );
document.write( "the slope intercept form of the perpendicuoar line is y = -x + b.\r<BR>\n" );
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document.write( "the perpendicular line goes thorough the point (0,4),.\r<BR>\n" );
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document.write( "the equation becomes y = -x + 4.<BR>\n" );
document.write( "-1 is the slope.<BR>\n" );
document.write( "4 is the y-intercept.\r<BR>\n" );
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document.write( "the y-intercept is the value of y when the vlaue os x = 0.\r<BR>\n" );
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document.write( "at the poijt (0,4), the value of x = 0 and the value of y = 4.\r<BR>\n" );
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document.write( "that makes y equal to the y-intercept.\r<BR>\n" );
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document.write( "your two equqtions are:\r<BR>\n" );
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document.write( "y = x - 2<BR>\n" );
document.write( "y = -2 + 4\r<BR>\n" );
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document.write( "these lines can be graphed as shown below.\r<BR>\n" );
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document.write( " </SPAN>\n" );
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