document.write( "Question 1180473: Joseph has $12500 to invest in two different accounts. Account 1 pays 9% interest and account 2 pays 12%. After a year, the interest paid by account 2 is twice the interest paid by account 1. How much money did Joseph invest in each account?
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Algebra.Com's Answer #810149 by mananth(16946)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "Joseph has $12500 to invest in two different accounts.
\n" ); document.write( "x in account 1
\n" ); document.write( "12500-x in account 2\r
\n" ); document.write( "\n" ); document.write( "Account 1 pays 9% interest and account 2 pays 12%.\r
\n" ); document.write( "\n" ); document.write( "9%x interest in account 1
\n" ); document.write( " 12%(12500-x) in account 2\r
\n" ); document.write( "\n" ); document.write( "Account 1 pays 9% interest and account 2 pays 12%.\r
\n" ); document.write( "\n" ); document.write( "12%(12500-x) =2*9%x \r
\n" ); document.write( "\n" ); document.write( "multiply equation by 100\r
\n" ); document.write( "\n" ); document.write( "12(12500-x) =18x\r
\n" ); document.write( "\n" ); document.write( "150000 -12x =18x
\n" ); document.write( "30x = 150000\r
\n" ); document.write( "\n" ); document.write( "x=5000\r
\n" ); document.write( "\n" ); document.write( "$5000 at 9%
\n" ); document.write( "$7500 at 12%\r
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