document.write( "Question 1180452: Nathan subscribes to an online computer service that charges Php 100 for 25 hours online and Php 6 for each hour
\n" ); document.write( "online in excess of 25 hours. Last month, his bill was Php 622. How many extra hours was he charged for? (using 1 variable)
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Algebra.Com's Answer #810143 by mananth(16946)\"\" \"About 
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C = 100+6x\r
\n" ); document.write( "\n" ); document.write( "where c is the total charge for x extra hours\r
\n" ); document.write( "\n" ); document.write( "last month she paid 622Php\r
\n" ); document.write( "\n" ); document.write( "622 = 100 +6x\r
\n" ); document.write( "\n" ); document.write( "522=6x\r
\n" ); document.write( "\n" ); document.write( "x=522/6\r
\n" ); document.write( "\n" ); document.write( "x=87 hours extra\r
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