document.write( "Question 1180448: Determine without converting the form and leave answer in the form of a+bi \r
\n" ); document.write( "\n" ); document.write( "(2-i)(3+4i) / ì-3 \n" ); document.write( "

Algebra.Com's Answer #810137 by ankor@dixie-net.com(22740) $\"\"$ $\"About$

You can put this solution on YOUR website!
Determine without converting the form and leave answer in the form of a+bi
\n" ); document.write( " $\"%28%282-i%29%283%2B4i%29%29%2F%28i%2B3%29\"$
\n" ); document.write( "same as
\n" ); document.write( " $\"%28%282-i%29%283%2B4i%29%29%2F%283%2Bi%29\"$
\n" ); document.write( "FOIL the numerator
\n" ); document.write( " $\"%286%2B8i-3i-4%28i%5E2%29%29%2F%283%2Bi%29\"$ = $\"%286%2B5i-4%28-1%29%29%2F%283%2Bi%29\"$ = $\"%286%2B5i%2B4%29%2F%283%2Bi%29\"$ = $\"%2810%2B5i%29%2F%283%2Bi%29\"$
\n" ); document.write( "multiply by the conjugate of the denominator over itself
\n" ); document.write( " $\"%2810%2B5i%29%2F%283%2Bi%29\"$ * $\"%283-i%29%2F%283-i%29\"$ = $\"%28%2810%2B5i%29%283-i%29%29%2F%28%283%2Bi%29%283-i%29%29\"$ = $\"%2830-10i%2B15i-5%28i%5E2%29%29%2F%289-i%5E2%29\"$ = $\"%2830%2B5i-5%28-1%29%29%2F%289-%28-1%29%29\"$ = $\"%2830%2B5i%2B5%29%2F10\"$ =
\n" ); document.write( " $\"%2835%2B5i%29%2F10\"$
\n" ); document.write( "cancel out 5
\n" ); document.write( " $\"%287%2Bi%29%2F2\"$ or (3.5 + .5i)
\n" ); document.write( " \n" ); document.write( "

\n" );