document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1180447>Question 1180447</A>: <I><SPAN STYLE=\"word-break: break-all;\"> From a bag containing 4 white and 6 black balls, two balls are drawn at random. If the <BR>\n" );
document.write( "balls are drawn one after the other without replacement, find the probability that <BR>\n" );
document.write( "3.1 both balls are white. <BR>\n" );
document.write( "3.2 both balls are black. <BR>\n" );
document.write( "3.3 the first ball is white and the second ball is black. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #810110 by </B><A HREF=/tutors/aboutme.mpl?userid=math_helper><B>math_helper(2461)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=math_helper><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=math_helper><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=810110\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 3.1  (4/10)*(3/9)<BR>\n" );
document.write( "3.2  (6/10)*(5/9)<BR>\n" );
document.write( "3.3  (4/10)*(6/9)<BR>\n" );
document.write( "<br><BR>\n" );
document.write( "<br><BR>\n" );
document.write( "NOTE that in 3.3, the order matters.   If we didn't care about order and just wanted P(you end up with one white and one black) = (6/10)*(4/9) + (4/10)*(6/9), which happens to be twice that found in 3.3, and is also equal to 1 - ((3.1) +(3.2)) which should make sense intuitively (you select two balls, they are either both black, both white, or one of each color).      </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );