document.write( "Question 1180400: Eight years ago Charles was 1 year older than twice David’s age then. In eight years, Charles will be 7/6 as old as David will be then. What is David’s age now ? \n" ); document.write( "

Algebra.Com's Answer #810050 by ewatrrr(24785) $\"\"$ $\"About$

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document.write( "Let c and d represent their respective ages NOW:\r\n" );
document.write( " c- 8 = 2(d-8) + 1\r\n" );
document.write( " c + 8 = (7/6)(d+8)\r\n" );
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document.write( "c  -   2d = -7\r\n" );
document.write( "c - (7/6)d = 56/6 - 48/6\r\n" );
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document.write( "- c  +   2d = 42/6\r\n" );
document.write( "  c - (7/6)d = 8/6\r\n" );
document.write( "       (5/6)d = 50/6\r\n" );
document.write( "            d = 10, David's age NOW\r\n" );
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document.write( "c = 13 NOW \r\n" );
document.write( "  5 = 2(2) + 1   checks   \r\n" );
document.write( "Wish You the Best in your Studies.\r\n" );
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