document.write( "Question 1180307: Find the tangent to each curve at the point where t = 3:
\n" ); document.write( "x = 5(t)^2, y = 10t\r
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\n" ); document.write( "\n" ); document.write( "answer is y = (1/3)x + 15
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Algebra.Com's Answer #810024 by greenestamps(13200)\"\" \"About 
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\n" ); document.write( "The point of tangency is (x(3),y(3)) = (45,30)

\n" ); document.write( "The slope of the tangent is the derivative of the curve at t=3.

\n" ); document.write( "\"dy%2Fdx=%28dy%2Fdt%29%2F%28dx%2Fdt%29+=+%2810%29%2F%2810t%29+=+1%2Ft\"

\n" ); document.write( "So at t=3 the slope is 1/3.

\n" ); document.write( "Use basic algebra with a slope of 1/3 and a point (45,30) to confirm the correctness of the answer you show.

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