document.write( "Question 1180329: What are three consecutive even integers if the sum of their squares is 1208? \n" ); document.write( "

Algebra.Com's Answer #809957 by ikleyn(52817) $\"\"$ $\"About$

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document.write( "The integers are (n-2), n and (n+2).\r\n" );
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document.write( "The equation to find \"n\" is\r\n" );
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document.write( "    (n-2)^2 + n^2 + (n+2)^2 = 1208\r\n" );
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document.write( "    n^2 - 2n + 4 + n^2 + n^2 + 2n + 4 = 1208\r\n" );
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document.write( "               3n^2                   = 1208 - 4 - 4 = 1200\r\n" );
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document.write( "                n^2                                  = 1200/3 = 400\r\n" );
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document.write( "                n                                             =  = +/- 20.\r\n" );
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document.write( "ANSWER.  There are two such sequences.\r\n" );
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document.write( "         One sequence is  18, 20, 22.  Another sequence is -22, -20, -18  (in ascending order).\r\n" );
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