document.write( "Question 111000: Janet invested $27,000, part at 15% and part at 9%. If the total interest at the end of the year is $3,390, how much did she invest at 15%? \n" ); document.write( "
Algebra.Com's Answer #80994 by scott8148(6628)![]() ![]() You can put this solution on YOUR website! let x=\"amount @ 15%\", so 27000-x=\"amount @ 9%\" ___ x(15%)+(27000-x)(9%)=3390\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( ".15x+2430-.09x=3390 \n" ); document.write( " |