document.write( "Question 16315: {2a+3b=12
\n" ); document.write( "{5a-b=13 please help me ,,,,thank you
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Algebra.Com's Answer #8099 by pwac(253)\"\" \"About 
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2a+3b=12-----(1)
\n" ); document.write( "5a-b=13------(2)re-arrangeto get
\n" ); document.write( "-b=13+5a
\n" ); document.write( "b=-13-5a substitute b in(1)
\n" ); document.write( "2a+3(-13-5a)=12 multiply bracket by 3
\n" ); document.write( "2a-39-15a=12 sum a-terms and add 39 to both sides
\n" ); document.write( "17a=51 divide both sides by 17
\n" ); document.write( "a=3 substitute this value of a into (1)
\n" ); document.write( "2(3)+3b=12
\n" ); document.write( "6+3b=12 subtract 6 from both sides
\n" ); document.write( "3b=6 divide both sides by3
\n" ); document.write( "b=2
\n" ); document.write( "a=3,b=2 substitute these into either equation to check
\n" ); document.write( "Pete
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