document.write( "Question 16315: {2a+3b=12
\n" );
document.write( "{5a-b=13 please help me ,,,,thank you \n" );
document.write( "
Algebra.Com's Answer #8099 by pwac(253)![]() ![]() ![]() You can put this solution on YOUR website! 2a+3b=12-----(1) \n" ); document.write( "5a-b=13------(2)re-arrangeto get \n" ); document.write( "-b=13+5a \n" ); document.write( "b=-13-5a substitute b in(1) \n" ); document.write( "2a+3(-13-5a)=12 multiply bracket by 3 \n" ); document.write( "2a-39-15a=12 sum a-terms and add 39 to both sides \n" ); document.write( "17a=51 divide both sides by 17 \n" ); document.write( "a=3 substitute this value of a into (1) \n" ); document.write( "2(3)+3b=12 \n" ); document.write( "6+3b=12 subtract 6 from both sides \n" ); document.write( "3b=6 divide both sides by3 \n" ); document.write( "b=2 \n" ); document.write( "a=3,b=2 substitute these into either equation to check \n" ); document.write( "Pete \n" ); document.write( " |