document.write( "Question 1180189: two fire-lookout stations are 29 miles apart, with station B directly east of station A. Both stations spot a fire. The bearing of the fire from station A is N35°E and the bearing of the fire from station B is N30°W. How far, to the nearest tenth of a mile, is the fire from each lookout station? \n" ); document.write( "
Algebra.Com's Answer #809865 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! two fire-lookout stations are 29 miles apart, with station B directly east of station A. \n" ); document.write( " Both stations spot a fire. \n" ); document.write( " The bearing of the fire from station A is N35°E and \n" ); document.write( " the bearing of the fire from station B is N30°W. \n" ); document.write( " How far, to the nearest tenth of a mile, is the fire from each lookout station? \n" ); document.write( ": \n" ); document.write( "Draw this out. Triangle ABC, where C is the point of the fire \n" ); document.write( "The line from A to B is horizontal to the the north-south lines so the interior angle of of the triangle: \n" ); document.write( "A = 90-35 = 55 degrees \n" ); document.write( "B = 90-30 = 60 degrees \n" ); document.write( "C = 180-55-60 = 65 degrees \n" ); document.write( ": \n" ); document.write( "label sides opposite the angles a, b, c \n" ); document.write( "Use the law of sine \n" ); document.write( " \n" ); document.write( "Cross multiply \n" ); document.write( "sin(65)*a = 29 * sin(55) \n" ); document.write( "a = \n" ); document.write( "a = 26.2 mi from B to the fire \n" ); document.write( "and \n" ); document.write( " \n" ); document.write( "Cross multiply \n" ); document.write( "sin(65)*b = 29 * sin(60) \n" ); document.write( "b = \n" ); document.write( "b = 27.7 mi from A to the fire\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |