document.write( "Question 1180245: log 12 1\r
\n" ); document.write( "\n" ); document.write( "12\r
\n" ); document.write( "\n" ); document.write( "1\r
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\n" ); document.write( "\n" ); document.write( "0
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Algebra.Com's Answer #809852 by Theo(13342)\"\" \"About 
You can put this solution on YOUR website!
log12(1) = y if and only if 12^y = 1 which occurs when y = 0 because 12^0 = 1.
\n" ); document.write( "your solution looks like it should be 0.
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