document.write( "Question 1180245: log 12 1\r
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document.write( "12\r
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document.write( "1\r
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document.write( "1/12\r
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document.write( "0 \n" );
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Algebra.Com's Answer #809852 by Theo(13342)![]() ![]() You can put this solution on YOUR website! log12(1) = y if and only if 12^y = 1 which occurs when y = 0 because 12^0 = 1. \n" ); document.write( "your solution looks like it should be 0. \n" ); document.write( " \n" ); document.write( " |