document.write( "Question 1180205: What are the possible number of positive, negative and imaginary zeros of:\r
\n" ); document.write( "\n" ); document.write( "f(x)= x^3 - 11x^2 + 8x - 20
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Algebra.Com's Answer #809834 by MathLover1(20850)\"\" \"About 
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\r
\n" ); document.write( "\n" ); document.write( "\"f%28x%29=+x%5E3+-+11x%5E2+%2B+8x+-+20\"\r
\n" ); document.write( "\n" ); document.write( "Use Decartes' rule of signs...\r
\n" ); document.write( "\n" ); document.write( "So, the coefficients are \"1\",\"-11\",\"8\",\"-20\"\r
\n" ); document.write( "\n" ); document.write( "As can be seen, there are \"3+\"changes.\r
\n" ); document.write( "\n" ); document.write( "This means that there are \"3+\"or \"1+\"positive real roots.\r
\n" ); document.write( "\n" ); document.write( "To find the number of negative real roots, substitute \"x\" with \"-x\" in the given polynomial: \r
\n" ); document.write( "\n" ); document.write( "\"x%5E3+-+11x%5E2+%2B+8x+-+20\" becomes \"-x%5E3+-+11x%5E2+-+8x+-+20\"\r
\n" ); document.write( "\n" ); document.write( "The coefficients are \"-1\",\"-11\",\"-8\",\"-20\".\r
\n" ); document.write( "\n" ); document.write( "As can be seen, there are\"+0\" changes.\r
\n" ); document.write( "\n" ); document.write( "This means that there are\"+0\" negative real roots.\r
\n" ); document.write( "\n" ); document.write( "Answer:\r
\n" ); document.write( "\n" ); document.write( "\"3\" or \"1\" positive real zeros \r
\n" ); document.write( "\n" ); document.write( "\"0\" negative real zeros\r
\n" ); document.write( "\n" ); document.write( "\"0\" or \"2\" imaginary zeros\r
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