document.write( "Question 1180193: The annual rainfall in a certain region is approximately normally distributed with mean 40.2 inches and standard deviation 5.9 inches. Round answers to the nearest tenth of a percent.\r
\n" ); document.write( "\n" ); document.write( "a) What percentage of years will have an annual rainfall of less than 44 inches? \r
\n" ); document.write( "\n" ); document.write( "b) What percentage of years will have an annual rainfall of more than 38 inches? \r
\n" ); document.write( "\n" ); document.write( "c) What percentage of years will have an annual rainfall of between 37 inches and 41 inches?
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Algebra.Com's Answer #809814 by ewatrrr(24785)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "Hi\r\n" );
document.write( "Normal Distribution:  µ = 40.2 and σ = 5.9\r\n" );
document.write( "Using TI or similarly an inexpensive calculator like a Casio fx-115 ES plus\r\n" );
document.write( "Continuous curve\r\n" );
document.write( "P(x < 44) = P(x ≤ 44) = normalcdf(-9999, 44, 40.2, 5.9) = .8284 0r 82.84%\r\n" );
document.write( "P(x > 38) = P(x ≥ 38) = normalcdf( 38, 9999, 40.2, 5.9) = .2123 0r 21.23%\r\n" );
document.write( "P(37 > x > 41)= normalcdf(37, 41, 40.2, 5.9) = .3829 = .0283 0r 2.83%\r\n" );
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document.write( "Important You feel comfortable using Your calculator.\r\n" );
document.write( "Wish You the Best in your Studies.\r\n" );
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